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36.x^2-x=42
We move all terms to the left:
36.x^2-x-(42)=0
We add all the numbers together, and all the variables
36.x^2-1x-42=0
a = 36.; b = -1; c = -42;
Δ = b2-4ac
Δ = -12-4·36.·(-42)
Δ = 6049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{6049}}{2*36.}=\frac{1-\sqrt{6049}}{72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{6049}}{2*36.}=\frac{1+\sqrt{6049}}{72} $
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